Prep 2
Math 2026
Term 1
First Term
Unit 1 - Algebra (Real Numbers)

Lesson 3 : Operations on Real Numbers - Notes

1. Like radical terms

A radical term has an index (root sign degree), a radical coefficient, and a radicand (the number under the root sign).

Example : in 4$\sqrt{2}$ $\rightarrow$ coefficient = 4 , index = 2 (square root) , radicand = 2.

Two radical terms are LIKE if they have the SAME index AND the SAME radicand.

  • 5$\sqrt{2}$ and -3$\sqrt{2}$ are like (same index 2, same radicand 2).
  • 5$\sqrt{2}$ and 5$\sqrt[3]{2}$ are NOT like (different indices).
  • 7$\sqrt{2}$ and 7$\sqrt{3}$ are NOT like (different radicands).

2. Addition and Subtraction

We can only add/subtract like radical terms by adding/subtracting their coefficients.

Examples :

  • $\sqrt{3}$ + 2$\sqrt{3}$ = (1 + 2)$\sqrt{3}$ = 3$\sqrt{3}$
  • 3$\sqrt{5}$ - 4$\sqrt{5}$ + $\sqrt{5}$ = (3 - 4 + 1)$\sqrt{5}$ = 0$\sqrt{5}$ = 0
  • 2$\sqrt{7}$ - 3$\sqrt{3}$ + $\sqrt{7}$ + 2$\sqrt{3}$ = (2 + 1)$\sqrt{7}$ + (-3 + 2)$\sqrt{3}$ = 3$\sqrt{7}$ - $\sqrt{3}$

3. Multiplication and Division

  • Multiply coefficients $\times$ coefficients and radicands $\times$ radicands : $\sqrt{3}$ $\times$ $\sqrt{3}$ = $\sqrt{9}$ = 3.
  • -5$\sqrt{2}$ $\times$ 3$\sqrt{2}$ = -15 $\times$ 2 = -30.
  • 2$\sqrt{3}$ $\times$ (4$\sqrt{3}$ / $\sqrt{7}$)... follow the same rule : coefficients together, radicands together.
  • The general rule : a$\sqrt{m}$ $\times$ b$\sqrt{n}$ = (a·b)$\sqrt{m·n}$
  • For division : a$\sqrt{m}$ ÷ b$\sqrt{n}$ = (a/b)$\sqrt{m/n}$.

4. Distributing and expanding

  • a(b + c) = ab + ac : 2($\sqrt{2}$ + $\sqrt{5}$) = 2$\sqrt{2}$ + 2$\sqrt{5}$.
  • (x + y)(x - y) = x² - y² : ($\sqrt{2}$ + 1)($\sqrt{2}$ - 1) = 2 - 1 = 1.
  • (x + y)² = x² + 2xy + y² : ($\sqrt{5}$ - 1)² = 5 - 2$\sqrt{5}$ + 1 = 6 - 2$\sqrt{5}$.
  • (4 - 3$\sqrt{2}$)(4 + 3$\sqrt{2}$) = 16 - 18 = -2.

5. Making the denominator an integer (Rationalizing)

  • Single radical denominator : multiply numerator and denominator by that radical.
  • Example : 6/$\sqrt{3}$ = (6$\sqrt{3}$)/($\sqrt{3}$·$\sqrt{3}$) = (6$\sqrt{3}$)/3 = 2$\sqrt{3}$.

  • Sum/difference with a radical : multiply by the CONJUGATE.
  • ($\sqrt{a}$ + $\sqrt{b}$) ↔ ($\sqrt{a}$ - $\sqrt{b}$) are conjugates; their product is a - b.

    Example : 1/($\sqrt{3}$ + 2) = ($\sqrt{3}$ - 2)/(($\sqrt{3}$ + 2)($\sqrt{3}$ - 2)) = ($\sqrt{3}$ - 2)/(3 - 4) = ($\sqrt{3}$ - 2)/(-1) = 2 - $\sqrt{3}$.

    Example : 20/(5 - $\sqrt{15}$) = 20(5 + $\sqrt{15}$)/(25 - 15) = 20(5 + $\sqrt{15}$)/10 = 2(5 + $\sqrt{15}$).

6. Useful area formulas

  • Cube with edge s : area of one face = s² , lateral area = 4s² , total area = 6s² , volume = s³.
  • Rectangular prism with dimensions l , w , h : total area = 2(lw + wh + hl) , volume = lwh.
  • Square with side x : area = x². Rectangle : area = length $\times$ width.

7. WORKED EXAMPLES

Example 1 : Simplify 2$\sqrt{5}$ - 3$\sqrt{5}$ + $\sqrt{5}$.

  • (2 - 3 + 1)$\sqrt{5}$ = 0. Answer : 0.

Example 2 : Find ($\sqrt{2}$ + 1)($\sqrt{2}$ - 1).

  • = ($\sqrt{2}$)² - (1)² = 2 - 1 = 1.

Example 3 : If x = -4$\sqrt{3}$ and y = $\sqrt{3}$, find x $\times$ y.

  • x $\times$ y = -4$\sqrt{3}$ $\times$ $\sqrt{3}$ = -4 $\times$ 3 = -12.

Example 4 : Find the area of a rectangle whose sides are (3$\sqrt{5}$ + 2) cm and (3$\sqrt{5}$ - 2) cm.

  • Area = (3$\sqrt{5}$ + 2)(3$\sqrt{5}$ - 2) = (3$\sqrt{5}$)² - (2)² = 45 - 4 = 41 cm².

Lesson Summary

Key Concepts with Solved Examples
1Adding and Subtracting Like Radicals
1 Example 1
Simplify 3*sqrt(2) + 5*sqrt(2).
  • 1Both terms have the same radical sqrt(2)
  • 2Add coefficients: 3 + 5 = 8
Final Answer: 8*sqrt(2)
2 Example 2
Simplify 4*sqrt(3) - 2*sqrt(3) + sqrt(3).
  • 2All terms have sqrt(3) $\rightarrow$ combine coefficients
  • 24 - 2 + 1 = 3
Final Answer: 3*sqrt(3)
2Multiplying and Dividing Radicals
1 Example 1
Simplify sqrt(3) * sqrt(12).
  • 2sqrt(3) * sqrt(12) = sqrt(3 * 12) = sqrt(36)
  • 2sqrt(36) = 6
Final Answer: 6
2 Example 2
Simplify (2*sqrt(5))(3*sqrt(10)).
  • 2Multiply coefficients: 2 * 3 = 6
  • 2Multiply radicals: sqrt(5) * sqrt(10) = sqrt(50)
  • 2Simplify sqrt(50) = sqrt(25 * 2) = 5*sqrt(2)
  • 2Final: 6 * 5*sqrt(2) = 30*sqrt(2)
Final Answer: 30*sqrt(2)
3Rationalizing Denominators
1 Example 1
Rationalize 5/sqrt(3).
  • 2Multiply top and bottom by sqrt(3)
  • 25*sqrt(3) / (sqrt(3)*sqrt(3)) = 5*sqrt(3) / 3
Final Answer: 5*sqrt(3)/3
2 Example 2
Rationalize 3/(sqrt(5) - 1).
  • 2Multiply by conjugate: (sqrt(5) + 1)/(sqrt(5) + 1)
  • 2Numerator: 3(sqrt(5) + 1) = 3sqrt(5) + 3
  • 2Denominator: (sqrt(5))² - 1² = 5 - 1 = 4
Final Answer: (3sqrt(5) + 3)/4